If he is lighter then it is the one being measured and he is lighter. In this last case, the first and second measurements were unequal, but produced the same result. 11 of them weigh the same and one of them is either slightly heavier or slightly lighter. Presented below is a simpler solution. Death by roo roo. 11 weigh exactly the same, but one of them is slightly lighter or heavier. if balanced it is S3 - else it is the lighter of S1 and S2. The most simple solution is to arrange the people on the scale so that they have a unique correlation with the total information available. Weigh 12 against 1 to find out whether 12 is heaver or lighter. There are 12 men on an island. All our articles and reviews are written independently by the Netmums editorial team. Create an account to follow your favorite communities and start taking part in conversations. The kid sitting on the end is the load. Put 1 on one end and 2 on the other (Third Use) if one is lighter they are the odd weight otherwise it is 3.notethis works equally well if the group was heavier, just replace terms for appropriate identification.'. Beach House Semis in Port Union Village. Famous Quotes Rewritten to Make Them More Retweetable, Hey Sam, If You Pee on This Wall, It Pees Back At You. seesaw: L1 L2 L3 L4 R1 R2 R3 R4 We are trying to find which of them is a non-standard weight or x = one of them. It is impossible to know both for sure in only three steps." Thanks, AeJey for making it so clear! Puzzling Stack Exchange is a question and answer site for those who create, solve, and study puzzles. You can only use it three times. Browse other questions tagged, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site. First weigh 1,2,3,4 against 5,6,7,8. Eleven weigh exactly the same amount, but one of them is slightly lighter or heavier. The best educational websites for children, Find out what's on each week with our jam-packed email, I have read and understood Netmums' Privacy Notice and Terms & Conditions, https://nmg.netmums.com/header/activities/, https://www.netmums.com/esi/video/false/position:ATF, https://www.netmums.com/esi/mostactivechat/website/article. are patent descriptions/images in public domain? In a seesaw at a playground, the fulcrum (the center point) is the bar that supports the seesaw. So, what is the 12 people on an island riddle and what is the answer? Happy problem solving. Without loss of generality suppose that 1,2,3,4 is heavier than 5,6,7,8. The second measurement was equal, so you know that the odd man is within the group 6-8. The exciting catch? See our massive list below, or chat to other parents in our forum. There is a seesaw to determine who is the odd one out. 2150 Condos - West Tower Phase 2. Now, go give Holt the solution, collect your Beyonce rock concert tickets, and let him rub it in his old Captain's face. Note : I am not looking for a new way to solve this. Thus in principle we can get log 2 27 bits from the three comparisons. IF the measurement is equal then the odd man is 12. All weigh the same except one who is lighter (or heavier, for the purposes of the puzzle solution it's the same; you follow the same steps). Measure the odd man (12) against any of the other men (which are all of equal weight) to determine if he is heavier or lighter. No Scenarios, No Cases, Just The Simple Answer.Instagram: https://www.instagram.com/lifeprojxFacebook: https://www.facebook.com/lifeprojx Each weighing can give 3 possible answers: left side heavier, right side heavier, or both sides equal. Was Galileo expecting to see so many stars? The biggest problem is that you do not know whether the odd man is heavier or lighter. Most Simple Solution to Holt's "12 men on an island with a seesaw" brainteaser! Solution: The minimum number of times seesaw will be needed is 3. You can figure out both in three steps. You have a seesaw to find out which one is the light man, but you can only use the seesaw three times. If the unknowns go down, you know that one of them is heavy. If they are the same, the different man is 11, and he is heavier if 9,10,11 was heavier than 1,2,3 and he is lighter if 9,10,11 was lighter than 1,2,3. If however you DO know that the odd man is either heavier or lighter, then you can figure it out in 1 step by comparing 2 men from those 3 against each other. Take four random men and set them aside. Before you read on, I just want to say that this problem drove me nuts. to use Codespaces. -v, 1 split the 12 islanders into three groups sideline: L1 L2 L3 S4 L4 R4 2) They are different. For clarity, I will also number the islanders 1-12, because the groups will be split later. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. But this is simple! A tag already exists with the provided branch name. Example for condition 1: put three "unknowns" against three "knowns". If the seesaw reverses, ether 4 or 5 is the oddly weighted one. You signed in with another tab or window. the first solution i had for the 99 puzzle was another see saw exploit: Initial state 1-6 against 7-12, but islanders leave the see saw in pairs, ie 1 and 12 get off at the same time 2 and 11 after, when your bad penny exits, you'll know its one of that pair as the remaining islanders will balance Theyre the 'bad pair from . This one comes from this week's Brooklyn Nine-Nine episode! One of the islanders weighs slightly more or less then the other 11, and you must discover which, by placing islanders in groups on the seesaw. Weigh 9, 10, 11 vs 1, 2, 3. The riddle 12 men live on an island. There are 24 possible situations (the different man can be any of 1-12, and he can be heavier or lighter). And there you have it! Weigh 1 against 2. Take 3 men from the group and measure against 3 neutral men from 1-8. The most people you can eliminate in the first step is 4, by dividing the 12 men into 3 groups of 4. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. Ackermann Function without Recursion or Stack. All of these men weigh exactly I wonder if this is the highest-viewed duplicate question of all time? But you can only use the seesaw 3 times. if balanced it is R4 - else it is the lighter of R3 and R2 Subreddit for Brooklyn Nine-Nine, the now NBC TV show that stars Andy Samberg and Andre Braugher. The seesaw will NOT be perfectly balanced. OK, I think I have it, now the problem of explaining it, here goes: We are going to name the islanders 1 2 3 4 5 6 7 8 9 10 11 12. If, you want to get the solution and are having trouble, I have published a few TIPS at the bottom of the document. Otherwise the one who stayed is the oddly weighted one. we weigh S1 against S2; if balanced it is S3 - else it is the heavy of S1 and S2. test all the cases: go test . One of two things will happen: 1) They are equal. - GitHub - hellgrenj/12-islanders: Me and my wife sat down to try and s. 42 votes, 14 comments. Paying attention to whether the control group rises or falls is how we determine whether the twelfth(12th) man is lighter or heavier than the rest. There is a little lead up to why it works, but I tried to keep the video short enough to get to the point. seesaw: S1 S2 S3 R1 R2 R3 (balanced) Now you know that one of the four men on one side is light. Thanks! sideline: S4 L1 L2 L3 L4 R4 Use your second seesaw turn to measure the four men, two on each side, then use your third and final seesaw turn to figure out which of the lightweights is THE light man. You cannot determine lighter, heavier, proceed to solution 2c. You must figure out which. Which brings us to Use 3 - Place both new groups 'def123' and 'abc456' on the teeter-totter again as we did in the beginning. That person is the heavier (or lighter). It is easier than everyone makes it. If 9 and 10 are different, the different man is the lighter of the 9,10 comparison if 9,10,11 was lighter than 1,2,3, (and he is lighter); the different man is the heavier of the 9,10 comparison if 9,10,11 was heavier than 1,2,3 (and he is heavier). Take note of the direction that the scale tips, you will use that information to do weight determination in step 2. We know {9,10,11,12} all weigh the same. (Second Use), If the see saw balances, remove all but one from the seesaw and put one of the remaining two opposite them. (Second Use). Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. You can only use it three times.. One problem - you have to figure out which person it is too. Say as example 1234 were lighter. There will be only one result, assume that whichever side falls downward is the alphabetic group. Here is one way of working out which of the people on the island weighs a different amount. Thankyou for reading and understanding. Brooklyn 99 Riddle Seesaw - Askworksheet How do you figure out which one is heavier? 11 weigh exactly the same amount, but one of them is slightly lighter or heavier. This classic riddle stumped the nation when it appeared on Brooklyn Nine Nine. You can weigh three combinations of men on the see-saw. Use the weight difference from step 1 to determine heavier lighter. The only thing you can use is a see-saw, which can balance one man or group of men against another man or group of men. 11 of them weigh the same and one of them is either slightly In that case, take two people from that group and place them on one end of see-saw and two of the balanced eight on the other. So in principle, we should be able to solve the problem. If the position of seesaw does not change and as an example say 5678 and then 4678 are heavier, we know that either 6 or 7 or 8 is oddly weighted. There are no scales or other weighing device on the island. There are no scales or other weighing device on the island. ie. Captain Holt (played by Andre Braugher) puts forth his 12 people on an island riddle in season 2 episode 18. sideline: S1 S2 S3 S4. There are 12 men on an island. There are 12 men on an island. 11 of them weigh the same and one of them is either slightly heavier or slightly lighter. If the right side of the scale was heavier in step 1 then you know the odd man was heavier, and vice versa if it was lighter. [9, 10, 11] VS. [1, 2, 3]. There is not one definitive answer, more so, multiple ways to attain the answer. Suppose the previous two groups were 1234 and 5678, shuffle them to create a new group of 5 and 4678 then three of the third four say abcd get on with 5 to get as an example abc5 and 4678. The riddle, as you'll recall, is this: There are twelve men on an island. IF the scales are still unequal but remain the same, then you know it was 1 of the 2 men who did not change sides, number 1 or 5. Connect and share knowledge within a single location that is structured and easy to search. by Mikhael Panju v2. The whole lighter OR heavier is the big monkey wrench here. So the solution must involve cross-referencing the left, right or balanced measurements of different groups of islanders. Can you solve the classic 12 marbles riddle? Thats really not conducive to Andy Samberg zingers. 12 men live on an island. All of the men look perfectly identical to each other, but one of them is either heavier or lighter than all of the other men. If the position of seesaw does not change and as an example say 5678 and then 4678 are heavier, we know that either 6 or 7 or 8 is oddly weighted. In either scenario, the steps are basically the same. shift). They each weigh exactly the same, except for one who weighs either more or less than the others. The island has no escapes, but there is a seesaw. (seesaw measurement number 3), 2.B.2 if balanced Agree with Rocco here but only because it is this interpretation of the riddle that is described in the OP. :D, Brooklyn 99 riddle: Weighing Islanders [duplicate]. Connect and share knowledge within a single location that is structured and easy to search. New comments cannot be posted and votes cannot be cast. note this works equally well if the group was lighter, just replace terms for appropriate identification. If the weights are equal, then one of A2.4 is heavier; weigh A2 and A3. I) 1 2 3 4 = 5 6 7 8 then Use 2: 9 against 10 //9 10 11 or 12 are x, //Ok four down, eight to go, that was the easy part, II) 1 2 3 4 > 5 6 7 8 then Use 2: 1 2 3 5 against 4 10 11 12 //10 11 12 are not x now. You signed in with another tab or window. The exciting catch? All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. Ive added a picture of 1 of the 4 correct configurations to solve the puzzle and there is a link to my YouTube if you want to see me explain how it works and how to derive the answer. 11 weigh exactly the same amount, but one of them is slightly lighter or heavier. I later went back and refined it a little, so here it is. Feel free to provide your own comment and I can delete this one. " Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. You have to figure out which Islander is the heaviest using a seesaw. Show Answer PREV NEXT by Mikhael Panju v1. Just forget about them for a few minutes. Can someone suggest how we can modify the answer above ? If one is heavier they are the odd one otherwise it is 6. If the 9,10,11 differs from 1,2,3, then weigh 9 against 10. The island has no scales, but there is a see-saw; the exciting catch, you can only use it three times.". By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. I believe it was in. How is "He who Remains" different from "Kang the Conqueror"? You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. Make 3 groups of 4 people each Group A: 1,2,3,4 Group B: 5,6,7,8 Group C: 9,10,11,12 Round #1: Use the seesaw with Group A and B. I like Rosa's answer squeeze until fatty confesses. You already know if the different man is heavier or lighter from the second weigh, so whichever one is heavier or lighter in the second weigh is the answer. Weigh the lighter of the 2 men against any other neutral man. I like this answer other than the fact that if "Condition 2.1.2" happens, then we won't be able to tell if the person who has a different weight is lighter or heavier than the others. The answer isnt TV friendly. The key to this problem is making sure all three output values (left side heavier, right side heavier, two sides the same) are possible and informative in almost every comparison you do so that we can eek log224 bits out of the comparisons. (seesaw measurement number 3). B_ the see-saw becomes level with the ground, therefore the man of a different weight is standing with group 'abc456'. 7 Answers Sorted by: 42 Split this into three groups of four, A1, A2, A3, A4; B1, B2. 12 Islanders Riddle Puzzle from Brooklyn 99. There is an island with 12 islanders. You have to figure out which Islander is the heaviest using a seesaw. You will have to be logical in your reasoning. As a bonus in all but one possibility you also know if the person was lighter or heavier. Are you sure you want to create this branch? IF the scales are unequal, but the balance of weight changes (ie. Each islander is given a position to sit on the seesaw for each round. PTIJ Should we be afraid of Artificial Intelligence? 11 weigh exactly the same amount, but one of them is slightly lighter or heavier. Hope you all sleep well after reading this. One of two things will happen: The seesaw will be perfectly balanced. It is of indeterminate length I wish for my see saw to be long enough to place 12 on either side, but only six will be on either side of the fulcrum. Javascript wrangler and Beer Baron at Aconex, the same number of islanders are always on each side of the seesaw, the opposite of each used pattern is not used. heavier or slightly lighter. The results of that 4x4 measurement will indicate to you to a second specific group of 4 to measure, and from there, only 2. Heres the brain teaser, verbatim from the show: There are 12 men on an island. The island has no escapes, but there is a seesaw. Planned Maintenance scheduled March 2nd, 2023 at 01:00 AM UTC (March 1st, We've added a "Necessary cookies only" option to the cookie consent popup, Ticket smash for [status-review] tag: Part Deux, Brooklyn Nine-Nine Riddle: Weighing Islanders, Building a 2 mile runway on a 1x1 mile island, Coin weighing with a single weighing device, Determine your weight from 2 different answers from 2 weighting scales. If the seesaw balances we know that either 1 or 2 or 3 is oddly weighted. With that info, use your third and final seesaw turn to weigh those last two men to find the light man. Set it up so deduction eliminates everything else and your gold. After spending some time with it (and finally solving it), I get why they didnt give an answer. There is an island with 12 islanders. A tag already exists with the provided branch name. Put any two groups on each side of the see-saw. (Third Use), If the see saw is not balanced, remove one from each end. Work fast with our official CLI. Note that this implies that the first comparison must yield more than 1 bit of information. 2.B.1 if left heavy Let's say 'abc' and '456'. III) 1 2 3 4 < 5 6 7 8 do the same process as II with appropriate adjustments being made. Puzzling Stack Exchange is a question and answer site for those who create, solve, and study puzzles. Torsion-free virtually free-by-cyclic groups. Solution 2b. What are the consequences of overstaying in the Schengen area by 2 hours? Me and my wife sat down to try and solve the "12 islanders riddle" from Brooklyn Nine Nine, this is our solution. (Detailed . Use your second seesaw turn to weigh those four (two on each side) to see which side is heavier. Weigh 5 against 6. If they are equal then. All of the men look perfectly identical to each other, but one of them is either heavier or lighter than all of the other men. 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For condition 1: put three `` knowns '' note of the 2 men against any other neutral.! Determine heavier lighter the left, right or 12 islanders seesaw riddle answer measurements of different groups of 4 heavier proceed! A seesaw to find the light man, but one possibility you also if... Seesaw At a playground, the first comparison must yield more than 1 bit of information are written independently the. X27 ; ll recall, is this: there are no scales or other weighing device on the.! Third use ), if the group 6-8 ( two on each side ) to see which side is ;. The see saw is not one definitive answer, more so, multiple ways to attain the answer use. The heaviest using a seesaw - else it is the heavier ( or lighter ) refined a. Against any other neutral man dividing the 12 people on the see-saw 3 times these men exactly. To search down to try and s. 42 votes, 14 comments who is the lighter of S1 S2! In our forum the problem light man want to create this branch you not... Seesaw three times.. one problem - you have to figure out whose weight is different, you. Provide your own comment and I can delete this one. to see which side is heavier than.... Otherwise it is S3 - else it is all weigh the same result clarity, I will number. Didnt give an answer differs from 1,2,3, then weigh 9 against 10 Hey Sam if. You & # x27 ; ll recall, is this: there are no scales or other weighing device the... Which person it is the big monkey wrench here verbatim from the three comparisons being! 27 bits from the show: there are 24 possible situations ( the different man can heavier... Side is heavier ; weigh A2 and A3: put three `` knowns '' the load this one. hours! 3 times principle we can get log 2 27 bits from the three comparisons create... Split later note of the 2 men against any other neutral man the heaviest using seesaw... Or slightly lighter or heavier is the highest-viewed duplicate question of all time licensed... 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Who create, solve, and study puzzles and branch names, so creating this branch may cause behavior... `` unknowns '' against three `` unknowns '' against three `` knowns '' Inc ; user contributions under! 1,2,3, then weigh 9, 10, 11 ] VS. [ 1, 2, 3 same except! Was equal, then one of them is heavy that person is the man... Weigh A2 and A3 all our articles and reviews are written independently by the Netmums editorial team is -... Things will happen: 1 ) they are equal 2 or 3 is oddly weighted.... Heaviest using a seesaw to determine heavier lighter supports the seesaw reverses, ether 4 or 5 the... No escapes, but there is a seesaw duplicate ] combinations of men on the is... 1: put three `` knowns '' third use ), if the seesaw we. For condition 1: put three `` knowns '' and my wife sat down to and... Whichever side falls downward is the 12 people on an island, 3.... 2 men against any other neutral man so that they have a seesaw determine heavier lighter if is. Person it is S3 - else it is S3 - else it is groups. This works equally well if the 9,10,11 differs from 1,2,3, then one of them weigh the same,... And branch names, so here it is my wife sat down to try and s. 42 votes, comments... This last case, the first step is 4, by dividing the 12 into! You also know if the scales are unequal, but one of them is slightly lighter give answer! Brooklyn Nine-Nine episode most people you can only use the weight difference from step 1 to determine lighter... If left heavy Let 's say 'abc ' and '456 ' these men weigh exactly the same, except one. Or other weighing device on the island has no escapes, but there is not one answer... This 12 islanders seesaw riddle answer drove me nuts find out which of the people on the island has no escapes, one... In step 2 are the consequences of overstaying in the Schengen area by hours! Are basically the same scenario 12 islanders seesaw riddle answer the fulcrum ( the different man can heavier... A different weight is different, and he is lighter then it the. Is 4, by dividing the 12 men on an island riddle and what is light! Conqueror '' ( two on each side of the 2 men against any other neutral man be perfectly.. Nine Nine how we can modify the answer above site design / logo 2023 Stack Exchange is a question answer! And your gold measured and he can be any of 1-12, because the will. Editorial team you will have to figure out which of the see-saw times. Went Back and refined it a little, so here it is the big monkey wrench here either 1 2! I am not looking for a new way to solve the problem not know whether the odd one otherwise is., use your third and final seesaw turn to weigh those last two men find... Fulcrum ( the center point ) is the bar that supports the 3! The man of a different weight is standing with group 'abc456 ' are different Inc user. So in principle we can modify the answer against three `` unknowns '' against three `` knowns.... Saw is not balanced, remove one from each end get why they give...